Integrand size = 25, antiderivative size = 112 \[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=-\frac {6 \sqrt {e \cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 a d e^2 \sqrt {\cos (c+d x)}}+\frac {6 \sin (c+d x)}{5 a d e \sqrt {e \cos (c+d x)}}-\frac {2}{5 d e \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))} \]
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Time = 0.08 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {2762, 2716, 2721, 2719} \[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=-\frac {6 E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{5 a d e^2 \sqrt {\cos (c+d x)}}+\frac {6 \sin (c+d x)}{5 a d e \sqrt {e \cos (c+d x)}}-\frac {2}{5 d e (a \sin (c+d x)+a) \sqrt {e \cos (c+d x)}} \]
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Rule 2716
Rule 2719
Rule 2721
Rule 2762
Rubi steps \begin{align*} \text {integral}& = -\frac {2}{5 d e \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))}+\frac {3 \int \frac {1}{(e \cos (c+d x))^{3/2}} \, dx}{5 a} \\ & = \frac {6 \sin (c+d x)}{5 a d e \sqrt {e \cos (c+d x)}}-\frac {2}{5 d e \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))}-\frac {3 \int \sqrt {e \cos (c+d x)} \, dx}{5 a e^2} \\ & = \frac {6 \sin (c+d x)}{5 a d e \sqrt {e \cos (c+d x)}}-\frac {2}{5 d e \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))}-\frac {\left (3 \sqrt {e \cos (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \, dx}{5 a e^2 \sqrt {\cos (c+d x)}} \\ & = -\frac {6 \sqrt {e \cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 a d e^2 \sqrt {\cos (c+d x)}}+\frac {6 \sin (c+d x)}{5 a d e \sqrt {e \cos (c+d x)}}-\frac {2}{5 d e \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.04 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.56 \[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=\frac {\operatorname {Hypergeometric2F1}\left (-\frac {1}{4},\frac {9}{4},\frac {3}{4},\frac {1}{2} (1-\sin (c+d x))\right ) \sqrt [4]{1+\sin (c+d x)}}{\sqrt [4]{2} a d e \sqrt {e \cos (c+d x)}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(305\) vs. \(2(124)=248\).
Time = 3.70 (sec) , antiderivative size = 306, normalized size of antiderivative = 2.73
method | result | size |
default | \(\frac {\frac {48 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )}{5}-\frac {24 \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {48 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )}{5}+\frac {24 \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}+\frac {16 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )}{5}-\frac {6 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, E\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )}{5}-\frac {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )}{5}}{\left (4 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-4 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1\right ) a \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, e d}\) | \(306\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.10 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.59 \[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=-\frac {3 \, {\left (i \, \sqrt {2} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + i \, \sqrt {2} \cos \left (d x + c\right )\right )} \sqrt {e} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) + 3 \, {\left (-i \, \sqrt {2} \cos \left (d x + c\right ) \sin \left (d x + c\right ) - i \, \sqrt {2} \cos \left (d x + c\right )\right )} \sqrt {e} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) + 2 \, \sqrt {e \cos \left (d x + c\right )} {\left (3 \, \cos \left (d x + c\right )^{2} - 3 \, \sin \left (d x + c\right ) - 2\right )}}{5 \, {\left (a d e^{2} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + a d e^{2} \cos \left (d x + c\right )\right )}} \]
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\[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=\frac {\int \frac {1}{\left (e \cos {\left (c + d x \right )}\right )^{\frac {3}{2}} \sin {\left (c + d x \right )} + \left (e \cos {\left (c + d x \right )}\right )^{\frac {3}{2}}}\, dx}{a} \]
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\[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=\int { \frac {1}{\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}} \,d x } \]
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\[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=\int { \frac {1}{\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{(e \cos (c+d x))^{3/2} (a+a \sin (c+d x))} \, dx=\int \frac {1}{{\left (e\,\cos \left (c+d\,x\right )\right )}^{3/2}\,\left (a+a\,\sin \left (c+d\,x\right )\right )} \,d x \]
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